# Problem: Nicotine, extracted from tobacco leaves, is a liquid completely miscible with water at temperatures below  60°C. What is the molality of nicotine (a covalent substance) in an aqueous solution that starts to freeze at -0.450°C? (Note that the Kf for water is 1.86 °C m -1)a) 2.42b) 0.0336c) 4.13d) 29.7e) 0.242

###### FREE Expert Solution
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###### FREE Expert Solution

We’re being asked to find the molality of a solution when nicotine is dissolved in water. When calculating the freezing point of a solution, we’re going to use the equation for Freezing Point Depression.

∆Tf = change in freezing point = Tf pure solvent –Tf solution
Kf = freezing point depression constant
i = van' t Hoff factor of the solute = no. of ions
m = molality

Determine the required values for the Freezing Point Depression equation:

98% (219 ratings)
###### Problem Details

Nicotine, extracted from tobacco leaves, is a liquid completely miscible with water at temperatures below  60°C. What is the molality of nicotine (a covalent substance) in an aqueous solution that starts to freeze at -0.450°C? (Note that the Kf for water is 1.86 °C m -1)

a) 2.42

b) 0.0336

c) 4.13

d) 29.7

e) 0.242

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Freezing Point Depression concept. If you need more Freezing Point Depression practice, you can also practice Freezing Point Depression practice problems.

What is the difficulty of this problem?

Our tutors rated the difficulty ofNicotine, extracted from tobacco leaves, is a liquid complet...as medium difficulty.

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What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Delgado's class at FIU.