🤓 Based on our data, we think this question is relevant for Professor Costanza's class at USF.
Solution: Rank the following aqueous solutions in order of decreasing boiling point.A. 0.020 m NaBr > 0.012 m KCl > 0.005 m SrCl2 > 0.012 m sucroseB. 0.020 m NaBr > 0.005 m SrCl2 > 0.012 m KCl = 0.012 m sucroseC. 0.005 m SrCl2 > 0.012 m KCl > = 0.012 m sucrose > 0.020 m NaBrD. 0.012 m sucrose > 0.012 m KCl > 0.005 m SrCl2 > 0.020 m NaBr
Problem
Rank the following aqueous solutions in order of decreasing boiling point.
A. 0.020 m NaBr > 0.012 m KCl > 0.005 m SrCl2 > 0.012 m sucrose
B. 0.020 m NaBr > 0.005 m SrCl2 > 0.012 m KCl = 0.012 m sucrose
C. 0.005 m SrCl2 > 0.012 m KCl > = 0.012 m sucrose > 0.020 m NaBr
D. 0.012 m sucrose > 0.012 m KCl > 0.005 m SrCl2 > 0.020 m NaBr
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