Ch.3 - Chemical ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: In the following reaction, the theoretical yield of Fe was calculated to be 105 g. If the actual yield was 87.9 g, what was the percent yield?Fe2O3 + 3CO → 2Fe + 3CO 2a) 65.3 %b) 83.7 %c) 112 %d) 97.8

Solution: In the following reaction, the theoretical yield of Fe was calculated to be 105 g. If the actual yield was 87.9 g, what was the percent yield?Fe2O3 + 3CO → 2Fe + 3CO 2a) 65.3 %b) 83.7 %c) 112 %d) 97.8

Problem

In the following reaction, the theoretical yield of Fe was calculated to be 105 g. If the actual yield was 87.9 g, what was the percent yield?

Fe2O3 + 3CO → 2Fe + 3CO 2

a) 65.3 %

b) 83.7 %

c) 112 %

d) 97.8 %

e) 59.0 %

 

Solution

We’re being asked to calculate the percent yield of Fe in the following reaction:


Fe2O3 + 3 CO  2 Fe + 3 CO2


Recall that percent yield is given by:



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