What is the percent yield of the reaction shown below if 29.6 g of gold (Au) are combined with 50.0 mL of 4.00 M HOCl (M = 54.46) in the presence of excess HCl, and 33.9 g of AuCl3 (M = 303.32) are obtained as a product? Enter your answer with 2 decimal places and no units.
2Au(s) + 3HCl(aq) + 3HOCl(aq) → 2AuCl3(s) + 3H2O(l)
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