We will calculate the amount of hydrogen gas (H2(g)) produced from Mg(s). The limiting reactant is Mg(s) since HCl(aq) is in excess.
Let’s first write the balanced reaction equation:
• aqueous magnesium chloride
▪ magnesium → group 2A → +2 charge → Mg2+
▪ chloride → group 7A → -1 charge → Cl-
*criss cross the charges of Mg2+ and Cl- and that would be the subscript of each ion
▪ aqueous magnesium chloride → MgCl2(aq)
• hydrogen gas → diatomic hydrogen gas → H2(g)
Consider the reaction between Mg(s) and HCl(aq) to produce aqueous magnesium chloride and hydrogen gas. What volume of hydrogen at STP will be produced when 12.15 g of magnesium reacts with an excess of hydrochloric acid?
A. 1.00 L
B. 2.00 L
C. 5.6 L
D. 11.2 L
E. 22.4 L
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