We’re being asked to calculate how many photons of the lowest possible frequency are required to ionize a sample of carbon. The first ionization energy of carbon is 1.81 aJ.
Ionization energy (IE) is the energy required to remove an electron from a gaseous atom or ion. Let’s calculate the ionization energy in J.
1 aJ = 10-18 J
IE = 1.81x10-18 J/atom
The ionization efficiency is 22.35%. Calculate the energy for 22.35% ionization efficiency:
% ionization efficiency = 22.35 %
Total energy = 1.81x10-18 J/atom
The first ionization energy of carbon is 1.81 aJ. Assuming an ionization efficiency of 22.35%, how many photons of the lowest possible frequency are required to ionize a sample of carbon that contains 5.32 x 1018 atoms?
a) 2.38 x 1019 photons
b) 4.20 x 10-20 photons
c) 2.73 x 1015 photons
d) 9.11 x 106 photons
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