What volume of 3.05 M HCl(aq) will react with 25.0 g Zn(s)?
Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)
a. 0.251 L
b. 4.01 L
c. 0.125 L
d. 0.0627 L
e. 2.33 L
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