# Problem: What volume of 3.05 M HCl(aq) will react with 25.0 g Zn(s)? Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)a. 0.251 Lb. 4.01 Lc. 0.125 Ld. 0.0627 Le. 2.33 L

###### Problem Details

What volume of 3.05 M HCl(aq) will react with 25.0 g Zn(s)?

Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)

a. 0.251 L

b. 4.01 L

c. 0.125 L

d. 0.0627 L

e. 2.33 L

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