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Problem: How many moles of Mg3P2 (s) can be produced from the reaction of 0.14 mol Mg(s) with 0.020 mol P4(s)?        _____Mg(s) + _____P4(s) →  _____Mg3P2(s)a. 0.047 molb. 0.14 molc. 0.42 mold. 0.020 mole. 0.040 mol 

FREE Expert Solution

We are asked to calculate the moles of Mg3P(s) can be produced from the reaction of 0.14 mol Mg(s) with 0.020 mol P4(s)?

We go through the following steps:

Step 1. Balance the reaction

Step 2. Calculate moles of product using both reactants

Step 3. Identify the limiting reactant (This produces the answer) 


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Problem Details

How many moles of Mg3P(s) can be produced from the reaction of 0.14 mol Mg(s) with 0.020 mol P4(s)?

        _____Mg(s) + _____P4(s) →  _____Mg3P2(s)

a. 0.047 mol

b. 0.14 mol

c. 0.42 mol

d. 0.020 mol

e. 0.040 mol

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.

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Our tutors rated the difficulty ofHow many moles of Mg3P2 (s) can be produced from the reactio...as medium difficulty.

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Based on our data, we think this problem is relevant for Professor Guerra's class at RUTGERS.