Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: What is the pH of 252.185 mL of a 3.52 x 10 -4 M HClO3 solution?A. 4.05B. 10.55C. 2.82D. 3.45E. the pH can't be calculated without the value of K a

Solution: What is the pH of 252.185 mL of a 3.52 x 10 -4 M HClO3 solution?A. 4.05B. 10.55C. 2.82D. 3.45E. the pH can't be calculated without the value of K a

Problem

What is the pH of 252.185 mL of a 3.52 x 10 -4 M HClO3 solution?

A. 4.05

B. 10.55

C. 2.82

D. 3.45

E. the pH can't be calculated without the value of K a

Solution

Remember that HClO3 is a strong, monoprotic oxyacid. It’s a strong oxyacid since there are 2 more O than H in the formula.


Recall that strong acids completely dissociate in water and that acids donate H+ to the base (water in this case). The dissociation of HClO4 is as follows:


HClO3(aq) + H2O(l)  H3O+(aq) + ClO3(aq)


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