Problem: A nuclide undergoes α decay and forms 110I. What is the nuclide? a. 114Csb. 114Ic. 110Ted. 112Cse. 110Xe

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We’re being asked to identify the starting nuclide for the nuclear reaction. 

It’s said that iodine–110 (11053I) is produced by alpha decay.


Recall that in a nuclear reaction, the number of protons and neutrons is affected and the identity of the element changes. For alpha decay, an alpha particle (42α, atomic mass = 4, atomic number = 2) is formed as a product.


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Problem Details

A nuclide undergoes α decay and forms 110I. What is the nuclide? 

a. 114Cs

b. 114I

c. 110Te

d. 112Cs

e. 110Xe

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