Chemistry Practice Problems Alpha Decay Practice Problems Solution: A nuclide undergoes α decay and forms 110I. What i...

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Solution: A nuclide undergoes α decay and forms 110I. What is the nuclide? a. 114Csb. 114Ic. 110Ted. 112Cse. 110Xe

Problem

A nuclide undergoes α decay and forms 110I. What is the nuclide? 

a. 114Cs

b. 114I

c. 110Te

d. 112Cs

e. 110Xe

Solution

We’re being asked to identify the starting nuclide for the nuclear reaction. 

It’s said that iodine–110 (11053I) is produced by alpha decay.


Recall that in a nuclear reaction, the number of protons and neutrons is affected and the identity of the element changes. For alpha decay, an alpha particle (42α, atomic mass = 4, atomic number = 2) is formed as a product.


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