Solution: Calculate the energy change for the reactionK(g) + Br(g) → K+(g) + Br– (g)given the following ionization energy (IE) and electron affinity (EA) valuesIE EAK: 419

Solution: Calculate the energy change for the reactionK(g) + Br(g) → K+(g) + Br– (g)given the following ionization energy (IE) and electron affinity (EA) valuesIE EAK: 419

Calculate the energy change for the reaction

K(g) + Br(g) → K^{+}(g) + Br^{–} (g)

given the following ionization energy (IE) and electron affinity (EA) values

__IE __ __EA__

K: 419 kJ/mol 48 kJ/mol

Br: 1140 kJ/mol 324 kJ/mol

A) –1,092 kJ/mol D) 1,092 kJ/mo

B) –95 kJ/mol E) 95 kJ/mol

C) 1,187 kJ/mol

We’re being asked to calculate the energy change (ΔE) for the given reaction given their respective ionization energies and electron affinities.

To calculate for the change in energy, we're going to use the following equation:

$\overline{){\mathbf{\u2206}}{\mathbf{E}}{\mathbf{=}}{\mathbf{I}}{\mathbf{o}}{\mathbf{n}}{\mathbf{i}}{\mathbf{z}}{\mathbf{a}}{\mathbf{t}}{\mathbf{i}}{\mathbf{o}}{\mathbf{n}}{\mathbf{}}{\mathbf{E}}{\mathbf{n}}{\mathbf{e}}{\mathbf{r}}{\mathbf{g}}{\mathbf{y}}{\mathbf{}}{\mathbf{\left(}}{\mathbf{I}}{\mathbf{E}}{\mathbf{\right)}}{\mathbf{+}}{\mathbf{E}}{\mathbf{l}}{\mathbf{e}}{\mathbf{c}}{\mathbf{t}}{\mathbf{r}}{\mathbf{o}}{\mathbf{n}}{\mathbf{}}{\mathbf{A}}{\mathbf{f}}{\mathbf{f}}{\mathbf{i}}{\mathbf{n}}{\mathbf{i}}{\mathbf{t}}{\mathbf{y}}{\mathbf{}}{\mathbf{\left(}}{\mathbf{E}}{\mathbf{A}}{\mathbf{\right)}}}$

**Recall:**

• **Ionization energy **is the energy required to * remove an electron* from a gaseous atom or ion.

• **Electron affinity** is the energy required to * add 1 mole of electrons* to a gaseous element.

** IE**

**K**: 419 kJ/mol 48 kJ/mol

**Br**: 1140 kJ/mol 324 kJ/mol