Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: What is the conjugate acid of CO 32– in the reactionCO32– + HSO4- ⇌ HCO3– + SO42–A) HCO3–             B) HSO4–                C) OH–                D) H3O+              E) SO42–

Solution: What is the conjugate acid of CO 32– in the reactionCO32– + HSO4- ⇌ HCO3– + SO42–A) HCO3–             B) HSO4–                C) OH–                D) H3O+              E) SO42–

Problem

What is the conjugate acid of CO 32– in the reaction
CO32– + HSO4⇌ HCO3 + SO42–

A) HCO3             

B) HSO4                

C) OH                

D) H3O+              

E) SO42–

Solution

We’re being asked to determine the conjugate acid of CO32– in the reaction:

CO32– + HSO4 HCO3 + SO42–


Recall that the conjugate acid of a base is simply the compound formed when a base gains a hydronium ion (H+). It's considered as an acid because it can lose H+ to reform the base.


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