Ch.14 - Chemical EquilibriumSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: When reaction 1 and 2 below are added together, the result i...

Problem

When reaction 1 and 2 below are added together, the result is reaction 3.

      1)  H 2O (l) + HNO (aq) ⇌ H 3O+ (aq) + NO 2‒ (aq)              1 = 4.50 × 10 ‒4

      2)  H 3(aq) + OH ‒ (aq) ⇌ 2 H 2O (l)                                   2 = 1.00 × 10 14

      3)  HNO (aq) + OH ‒ (aq) ⇌ NO 2‒ (aq) + H 2O (l)                3=?

Find the equilibrium constant, 3.           

 

A) 4.50 × 10‒18              B) 2.22 × 1017              C) 4.50 × 1010                 D) 1.00 × 1014