Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Trimethylamine, N(CH3)3, is the molecule that is responsible for the “fishy smell” of seafood. It has a Kb of 6.3 x 10 -5, making it a moderately-strong weak base.   A. Write a balanced chemical equ

Problem

Trimethylamine, N(CH3)3, is the molecule that is responsible for the “fishy smell” of seafood. It has a Kb of 6.3 x 10 -5, making it a moderately-strong weak base.

 

A. Write a balanced chemical equation showing how N(CH 3)3 acts as a weak base in water.

 

B. Now consider the ionic compound HN(CH 3)3Cl, formed by reacting N(CH3)3 with HCl. In water, HN(CH3)3Cl separates into HN(CH3)3+(aq) and one of our favorite spectator ions, Cl -(aq). Calculate the pH of 0.18 M HN(CH 3)3Cl.

 

 

1. Write a balanced chemical equation for the acid-base reaction your calculation is based on. You do not need to include Cl(aq) because it is a spectator.

 

 

 

 

2. Determine the pH of this solution.

 

 

 

 

3. Is the pH you calculated consistent with the chemical equation you wrote for Part B.1?