Ch.12 - SolutionsWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Determine the molality of an aqueous solution prepared by dissolving 0.112 moles of LiCl in 13.7 moles of H 2 O.A) 0.122 mB) 0.454 mC) 0.220 mD) 0.818 mE) 0.153 m

Solution: Determine the molality of an aqueous solution prepared by dissolving 0.112 moles of LiCl in 13.7 moles of H 2 O.A) 0.122 mB) 0.454 mC) 0.220 mD) 0.818 mE) 0.153 m

Problem

Determine the molality of an aqueous solution prepared by dissolving 0.112 moles of LiCl in 13.7 moles of H 2 O.

A) 0.122 m

B) 0.454 m

C) 0.220 m

D) 0.818 m

E) 0.153 m

Solution

We’re being asked to calculate for the molality of an aqueous solution prepared by dissolving 0.112 moles of LiCl in 13.7 moles of H2O. 

When calculating for molality, we use the following equation:


Aqueous solution → water is the solvent

Solute → LiCl

The moles of the solute is already given. 

We will calculate the molality of the solution using the following steps:

Step 1. Calculate the mass of the solvent (in kg).
Step 2. Calculate the molality of the solution.


Step 1. Calculate the mass of the water (in kg).

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