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Problem: Zinc (II) sulfide reacts with oxygen according to the reaction: 2 ZnS(s) + 3 O2(g)  → 2 ZnO(s) + 2 SO2(g) A reaction mixture initially contains 4.2 mol ZnS and 6.8 mol O2. Once the reaction has occured as completely as possible, what amount (in moles) of the excess reactant is left? A. 1.5 mol B. 0.5 mol C. 6.3 mol D. 0 mol

🤓 Based on our data, we think this question is relevant for Professor Wojcinski's class at OREGONSTATE.

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Problem Details

Zinc (II) sulfide reacts with oxygen according to the reaction:

2 ZnS(s) + 3 O2(g)  → 2 ZnO(s) + 2 SO2(g)

A reaction mixture initially contains 4.2 mol ZnS and 6.8 mol O2. Once the reaction has occured as completely as possible, what amount (in moles) of the excess reactant is left?

A. 1.5 mol

B. 0.5 mol

C. 6.3 mol

D. 0 mol

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