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Chemical Equilibrium

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Sections
Chemical Equilibrium	61 mins	0 completed	Learn Summary
ICE Chart	52 mins	0 completed	Learn
Le Chatelier's Principle	24 mins	0 completed	Learn Summary
The Reaction Quotient	11 mins	0 completed	Learn Summary

Additional Guides
Equilibrium Expressions

Learn Additional Practice Summary

Next SectionICE Chart

Solution: Consider the reactions SO₂(g) → O₂(g) + S(s) K _c = 2.5 × 10−53 SO₃(g) → 1/2 O₂(g) + SO₂(g) K _c = 4.0 × 10−13Calculate K_c for the reaction 2 S(s) + 3O₂(g) → 2 SO₃(g).1. 1.6 × 101032. 1.0 × 10653. 1.6 × 10804. 1.0 × 101305. 1.6 × 1040

Solution: Consider the reactionsSO2(g) → O2(g) + S(s) K c = 2.5 × 10−53SO3(g) → 1/2 O2(g) + SO2(g) K c = 4.0 × 10−13Calculate Kc for the reaction2 S(s) + 3O2(g) → 2 SO3

Problem

Consider the reactions
SO₂(g) → O₂(g) + S(s) K _c = 2.5 × 10⁻⁵³
SO₃(g) → 1/2 O₂(g) + SO₂(g) K _c = 4.0 × 10⁻¹³

Calculate K_c for the reaction
2 S(s) + 3O₂(g) → 2 SO₃(g).

1. 1.6 × 10¹⁰³

2. 1.0 × 10⁶⁵

3. 1.6 × 10⁸⁰

4. 1.0 × 10¹³⁰

5. 1.6 × 10⁴⁰

Chemical Equilibrium

Solution: Consider the reactions SO2(g) → O2(g) + S(s) K c = 2.5 × 10−53 SO3(g) → 1/2 O2(g) + SO2(g) K c = 4.0 × 10−13Calculate Kc for the reaction 2 S(s) + 3O2(g) → 2 SO3(g).1. 1.6 × 101032. 1.0 × 10653. 1.6 × 10804. 1.0 × 101305. 1.6 × 1040

Solution: Consider the reactionsSO2(g) → O2(g) + S(s) K c = 2.5 × 10−53SO3(g) → 1/2 O2(g) + SO2(g) K c = 4.0 × 10−13Calculate Kc for the reaction2 S(s) + 3O2(g) → 2 SO3

Problem

Practice Problems

Solution: Consider the reactions SO₂(g) → O₂(g) + S(s) K _c = 2.5 × 10−53 SO₃(g) → 1/2 O₂(g) + SO₂(g) K _c = 4.0 × 10−13Calculate K_c for the reaction 2 S(s) + 3O₂(g) → 2 SO₃(g).1. 1.6 × 101032. 1.0 × 10653. 1.6 × 10804. 1.0 × 101305. 1.6 × 1040