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# Problem: At 25 oC, ΔHo = 1.895 kJ and ΔSo = – 3.363 J/K for the transition  C (graphite) →  C (diamond) Based on their data a) Graphite is more stable than diamond below 290 oC and diamond is more stable than graphite above 290 oC.  b) Graphite cannot be converted to diamond at 1 atm pressure.  c) Diamond is more stable than graphite at all temperatures at 1 atm.  d) Diamond is more stable than graphite below 290 oC and graphite is more stable than diamond above 290 oC.

###### Problem Details

At 25 oC, ΔHo = 1.895 kJ and ΔSo = – 3.363 J/K for the transition

C (graphite) →  C (diamond)

Based on their data

a) Graphite is more stable than diamond below 290 oC and diamond is more stable than graphite above 290 oC.

b) Graphite cannot be converted to diamond at 1 atm pressure.

c) Diamond is more stable than graphite at all temperatures at 1 atm.

d) Diamond is more stable than graphite below 290 oC and graphite is more stable than diamond above 290 oC.

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Spontaneous Reaction concept. You can view video lessons to learn Spontaneous Reaction. Or if you need more Spontaneous Reaction practice, you can also practice Spontaneous Reaction practice problems.

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Our tutors rated the difficulty ofAt 25 oC, ΔHo = 1.895 kJ and ΔSo = – 3.363 J/K for the trans...as high difficulty.

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Based on our data, we think this problem is relevant for Professor Blankenship's class at UGA.