Ch.14 - Chemical EquilibriumSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Equilibrium Expressions

See all sections
Sections
Chemical Equilibrium
ICE Chart
Le Chatelier's Principle
The Reaction Quotient
Additional Practice
Equilibrium Expressions

Solution: The  equilibrium constant for the reaction                               2 H   2 (g)  +   CO (g) ⇌ CH 3OH (g) is 1.6 x 10-8 at a certain temperature. If there are 1.17 moles of H 2 and 3.46 moles of CH3OH at equilibrium in a 5.60 L flask, how many moles of CO are present at equilibrium? 

Problem

The  equilibrium constant for the reaction 

                              2 H   2 (g)  +   CO (g) ⇌ CH 3OH (g) 

is 1.6 x 10-8 at a certain temperature. If there are 1.17 moles of H 2 and 3.46 moles of CH3OH at equilibrium in a 5.60 L flask, how many moles of CO are present at equilibrium?