Ch.16 - Aqueous Equilibrium WorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Equivalence Point

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Sections
Buffer
Acid and Base Titration Curves
Weak Acid Strong Base Titrations
Weak Base Strong Acid Titrations
Strong Acid Strong Base Titrations
Titrations of Diprotic and Polyprotic Acids
Ksp
Additional Practice
Equivalence Point
Acid Base Indicators
Selective Precipitation
Formation Constant
Additional Guides
Henderson Hasselbalch Equation
Additional Practice

Solution: A chemistry student weighs out 0.0899 g of acetic acid, HC 2H3O2 into a 250 mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1900 M NaOH solution.

Solution: A chemistry student weighs out 0.0899 g of acetic acid, HC 2H3O2 into a 250 mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1900 M NaOH solution.

Problem

A chemistry student weighs out 0.0899 g of acetic acid, HC 2H3O2 into a 250 mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1900 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point.

a) 3.07 mL

b) 4.08 mL

c) 5.48 mL

d) 6.15 mL

e) 7.88 mL

Solution

We’re being asked to calculate the volume of 0.1900 M NaOH required to titrate 0.0899 g acetic acid (HC2H3O2) to the equivalence point.


The reaction between HC2H3O2 and NaOH will be a double displacement reaction where H+ reacts with OH– and C2H3O2– reacts with Na+. 


The overall reaction is:

HC2H3O2 + NaOH → H2O + NaC2H3O2


Recall that at the equivalence point of a titration:



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