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Solution: Calculate the pressure of O2 necessary to generate an aqueous solution that is 6.0 x 10‐2 M in O 2 at 25° C. The Henry’s law constant for  O 2 in water at 25°C is 1.3 x 10 ‐3 mole/L•atmA) 7.8 x 10‐5 atmB) 2.1 x 10‐2 atmC) 46 atmD) 1.28 x 104 atmE) none of these   

Problem

Calculate the pressure of O₂ necessary to generate an aqueous solution that is 6.0 x 10^‐2 M in O ₂ at 25° C. The Henry’s law constant for  O ₂ in water at 25°C is 1.3 x 10 ^‐3 mole/L•atm

A) 7.8 x 10^‐5 atm
B) 2.1 x 10^‐2 atm
C) 46 atm
D) 1.28 x 10⁴ atm
E) none of these

 

 

 

Solution

We’re being asked to determine the partial pressure of O₂ at 25 ˚C to produce a solution of 6.0 × 10^–2 M. Recall that the solubility of a gas is given by Henry’s law:

where S_gas = solubility of the gas (in mol/L or M), k_H = Henry’s law constant for the gas, P_gas = partial pressure of the gas.

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