Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction:
P4(g) + 10Cl2(g) → 4PCl5(s) ΔH°rxn = ?
PCl5(s) → PCl3(g) + Cl2(g) ΔH°rxn = +157kJ
P4(g) + 6Cl2(g) → 4PCl3(g) ΔH°rxn = -1207kJ
A) -1835 kJ
B) - 1364 kJ
C) -1050 kJ
E) -2100 kJ
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