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Problem: A mixture of 45.2 g of PbO (molar mass 223.2 g/mol) and 35.4 g PbS ( molar mass 239.3 g/mol) are allowed to react. Identify the limiting  reagent and determine the maximum mass of lead (molar mass 207.2 g/mol) that can be obtained by the reaction. 2PbO(s) + PbS(s) → 3Pb(s) + SO2(g) A) PbS limiting; 30.65 g Pb obtained. B) PbS limiting; 91.95 g Pb obtained. C) PbO limiting; 63.0 g Pb obtained. D) PbO limiting; 42.0 g Pb obtained.

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Problem Details

A mixture of 45.2 g of PbO (molar mass 223.2 g/mol) and 35.4 g PbS ( molar mass 239.3 g/mol) are allowed to react. Identify the limiting  reagent and determine the maximum mass of lead (molar mass 207.2 g/mol) that can be obtained by the reaction.

2PbO(s) + PbS(s) → 3Pb(s) + SO2(g)

A) PbS limiting; 30.65 g Pb obtained.

B) PbS limiting; 91.95 g Pb obtained.

C) PbO limiting; 63.0 g Pb obtained.

D) PbO limiting; 42.0 g Pb obtained.

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