A mixture of 45.2 g of PbO (molar mass 223.2 g/mol) and 35.4 g PbS ( molar mass 239.3 g/mol) are allowed to react. Identify the limiting reagent and determine the maximum mass of lead (molar mass 207.2 g/mol) that can be obtained by the reaction.
2PbO(s) + PbS(s) → 3Pb(s) + SO2(g)
A) PbS limiting; 30.65 g Pb obtained.
B) PbS limiting; 91.95 g Pb obtained.
C) PbO limiting; 63.0 g Pb obtained.
D) PbO limiting; 42.0 g Pb obtained.
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