According to the following balanced reaction, how many moles of Fe(OH) 2 can form from 175.0 mL of 0.227 M LiOH solution? Assume that there is excess FeCl2.
FeCl2(aq) + 2 LiOH(aq) → Fe(OH)2(s) + 2 LiCl(aq)
A) 3.97 × 10−2 moles
B) 2.52 × 10−2 moles
C) 1.99 × 10−2 moles
D) 5.03 × 10−2 moles
E) 6.49 × 10−2 moles
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