Ch.15 - Acid and Base EquilibriumSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Given the Ka values (in parentheses) for the following acids: HCl (Ka is very large) HNO2 (Ka = 4.0 x 10 –4 ); HF (Ka = 7.2 x 10 –4 ) CH3COOH (Ka = 1.8 x 10 –5 ) HCN (Ka = 6.2 x 10 –10) C6H5COOH (Ka = 6.3 x 10 –5 ) Rank (or list) these acids in order of decreasing strength (strongest first). A. HCl > HF > HNO2 > C6H5COOH > CH3COOH > HCN B. HCl > HF > HNO2 > CH3COOH > C6H5COOH > HCN C. HCN > CH3COOH > C6H5COOH > HNO2 > HF > HCl D. HCl > HNO2 > HF > CH3COOH > C6H5COOH > HCN E. HCN > C6H5COOH > CH3COOH > HF > HNO2 > HCl

Problem

Given the Ka values (in parentheses) for the following acids:

HCl (Ka is very large)

HNO2 (Ka = 4.0 x 10 –4 );

HF (Ka = 7.2 x 10 –4 )

CH3COOH (Ka = 1.8 x 10 –5 )

HCN (Ka = 6.2 x 10 –10)

C6H5COOH (Ka = 6.3 x 10 –5 )

Rank (or list) these acids in order of decreasing strength (strongest first).

A. HCl > HF > HNO2 > C6H5COOH > CH3COOH > HCN

B. HCl > HF > HNO2 > CH3COOH > C6H5COOH > HCN

C. HCN > CH3COOH > C6H5COOH > HNO2 > HF > HCl

D. HCl > HNO2 > HF > CH3COOH > C6H5COOH > HCN

E. HCN > C6H5COOH > CH3COOH > HF > HNO2 > HCl