Ch.4 - Chemical Quantities & Aqueous ReactionsSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Calculate the molarity of acetate ions from a solution prepared by diluting 52.7 mL of 0.250 M tin (IV) acetate to 250 mL. a. 0.2108 M C2H3C2- b. 0.0527M C2H3C2- c. 1.1850 M C2H3C2- d. 0.1054 M C2H3C2-

Problem

Calculate the molarity of acetate ions from a solution prepared by diluting 52.7 mL of 0.250 M tin (IV) acetate to 250 mL.

a. 0.2108 M C2H3C2-

b. 0.0527M C2H3C2-

c. 1.1850 M C2H3C2-

d. 0.1054 M C2H3C2-