# Problem: Place the following in order of decreasing dipole moment.I. cis-CHCl=CHClII. trans-CHCl=CHCIIII. cis-CHF=CHF A) III &gt; I &gt; IIB) II &gt; I &gt; IIIC) I &gt; III &gt; IID) II &gt; III &gt; IE) I = III &gt; II

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Place the following in order of decreasing dipole moment.

I. cis-CHCl=CHCl

II. trans-CHCl=CHCI

III. cis-CHF=CHF

A) III > I > II

B) II > I > III

C) I > III > II

D) II > III > I

E) I = III > II

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