Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Given: acetic acid, pKa = 4.75 HClO2, pKa = 2.00 HF, pKa = 3.45 The order of these acids from strongest to weakest is a) HClO2 > HF > acetic acid b) acetic acid > HF > HClO 2 c) HF > HClO 2 > acetic acid d) HClO2 > acetic acid > HF e) HF > acetic acid > HClO 2

Problem

Given:

acetic acid, pKa = 4.75

HClO2, pKa = 2.00

HF, pKa = 3.45

The order of these acids from strongest to weakest is

a) HClO2 > HF > acetic acid

b) acetic acid > HF > HClO 2

c) HF > HClO 2 > acetic acid

d) HClO2 > acetic acid > HF

e) HF > acetic acid > HClO 2