🤓 Based on our data, we think this question is relevant for Professor Mohammadi's class at CSULB.
Solution: How many grams of oxygen are formed when 6.21 moles of KOH are formed?
4 KO (s) + 2 H2O (l) → 4 KOH (s) + O2 (g)
A) 11.7 g O2
B) 27.9 g O2
C) 3.59 g O2
D) 19.9 g O2
E) 49.7 g O2