# Problem: How many grams of oxygen are formed when 6.21 moles of KOH are formed?  4 KO (s) + 2 H2O (l) → 4 KOH (s) + O2 (g) A) 11.7 g O2 B) 27.9 g O2 C) 3.59 g O2 D) 19.9 g O2 E) 49.7 g O2

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How many grams of oxygen are formed when 6.21 moles of KOH are formed?

4 KO (s) + 2 H2O (l) → 4 KOH (s) + O(g)

A) 11.7 g O2

B) 27.9 g O2

C) 3.59 g O2

D) 19.9 g O2

E) 49.7 g O2

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Our tutors have indicated that to solve this problem you will need to apply the Stoichiometry concept. You can view video lessons to learn Stoichiometry. Or if you need more Stoichiometry practice, you can also practice Stoichiometry practice problems.

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Based on our data, we think this problem is relevant for Professor Mohammadi's class at CSULB.