Ch.1 - Intro to General ChemistryWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The estimated mass of the planet Jupiter is 1.90 × 10 27 kg and the density is believed to be 1.34 g/cm3. If Jupiter were a perfect sphere, what would be its diameter?A) 6.96 × 107 m                  

Solution: The estimated mass of the planet Jupiter is 1.90 × 10 27 kg and the density is believed to be 1.34 g/cm3. If Jupiter were a perfect sphere, what would be its diameter?A) 6.96 × 107 m                  

Problem

The estimated mass of the planet Jupiter is 1.90 × 10 27 kg and the density is believed to be 1.34 g/cm3. If Jupiter were a perfect sphere, what would be its diameter?

A) 6.96 × 107 m                         

B) 1.39 × 107 m                        

C) 1.39 × 108 m                      

D) 6.96 × 106 m

Solution

We’re being asked to determine the diameter of Jupiter given that it has a mass of 1.90 × 1027 kg and a density of 1.34 g/cm3.


Recall that density is the ratio of the mass and volume of an object:


density=massvolume


Also, the volume of a sphere is given by:


V=43πr3


where:

 r = radius. Recall that diameter = 2r.


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