We’re being asked to **determine the diameter of Jupiter** given that it has a **mass of 1.90 × 10 ^{27} kg** and a

Recall that ** density** is the ratio of the mass and volume of an object:

$\overline{){\mathbf{density}}{\mathbf{=}}\frac{\mathbf{mass}}{\mathbf{volume}}}$

Also, the ** volume of a sphere** is given by:

$\overline{){\mathbf{V}}{\mathbf{=}}\frac{\mathbf{4}}{\mathbf{3}}{{\mathbf{\pi r}}}^{{\mathbf{3}}}}$

where:

**r** = radius. Recall that diameter = 2r.

The estimated mass of the planet Jupiter is 1.90 × 10 ^{27} kg and the density is believed to be 1.34 g/cm^{3}. If Jupiter were a perfect sphere, what would be its diameter?

A) 6.96 × 10^{7} m

B) 1.39 × 10^{7} m

C) 1.39 × 10^{8} m

D) 6.96 × 10^{6} m

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Based on our data, we think this problem is relevant for Professor Mundell's class at CSU OHIO.