Ch.13 - Chemical KineticsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: When the concentration of A is doubled, the rate for the reaction: 2 A + B → 2 C quadruples.When the concentration of B is doubled the rate remains the same. Which mechanism below is consistent with t

Solution: When the concentration of A is doubled, the rate for the reaction: 2 A + B → 2 C quadruples.When the concentration of B is doubled the rate remains the same. Which mechanism below is consistent with t

Problem

When the concentration of A is doubled, the rate for the reaction: 2 A + B → 2 C quadruples.

When the concentration of B is doubled the rate remains the same. Which mechanism below is consistent with the experimental observations?     

 

A) Step 1:  A + B → D (slow)

Step 2:  A + D → 2 C (fast)     

 

B) Step 1:   A → D (slow)

Step 2:  A + B + D → E (fast)

Step 3:  E → 2 C (fast)

 

C) Step 1:  2 A → D (slow)

Step 2:  B + D → E (fast)

Step 3:  E → 2 C (fast)     

 

D) Step 1:  A + B → D (slow)

Step 2:  A + D ⇌ 2 C (fast equilibrium)

Solution

We’re being asked to determine the reaction mechanism that is consistent with the given experimental observations for this reaction:

2 A + B  2 C


Recall that a reaction mechanism is a sequence of single steps that add up to the chemical reaction

The rate law of the reaction depends on the rate-determining step of the mechanism, which is the slow step in the mechanism


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