Ch.7 - Quantum MechanicsSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution:  For a hydrogen atom, calculate the energy (in kJ) of a photon in the Balmer series that results from the transition n = 5 to n = 2. a. 1.09x10 -20 kJ b. 2.04x10 -21 kJ c. 2.18x10 -21 kJ d. 3.03x10 -22 kJ e. 4.58x10 -22 kJ

Problem

 For a hydrogen atom, calculate the energy (in kJ) of a photon in the Balmer series that results from the transition n = 5 to n = 2.

a. 1.09x10 -20 kJ

b. 2.04x10 -21 kJ

c. 2.18x10 -21 kJ

d. 3.03x10 -22 kJ

e. 4.58x10 -22 kJ