Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: What are the oxidation numbers of chlorine on the reactant side and on the product side in the following redox reaction? 2 OH - (aq)  +  Cl2O7 (g)  +   4 H2O2 (aq)  →  2 ClO2 - (aq)  +   4 O2 (g)  +   5 H2O (l)  A. Reactant: –1; product: +3 B. Reactant: +7; product: +3 C. Reactant: +14; product: –1 D. Reactant: +7; product: +4 E. Reactant: 0; product: –1

Problem

What are the oxidation numbers of chlorine on the reactant side and on the product side in the following redox reaction?

2 OH - (aq)  +  Cl2O7 (g)  +   4 H2O2 (aq)  →  2 ClO2 - (aq)  +   4 O2 (g)  +   5 H2O (l) 

A. Reactant: –1; product: +3

B. Reactant: +7; product: +3

C. Reactant: +14; product: –1

D. Reactant: +7; product: +4

E. Reactant: 0; product: –1