All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: According to the equation 2 KCIO 3(s) → 2 KCI(s) + 3 O 2(g)A 3.00 g sample of KCIO 3 (122.5 g/mol) decomposes and the oxygen is collected over water at 24.0°C and 0.982 atm. What volume of oxygen gas will be collected, assuming 100% yield? P(H 2O) at 24.0°C = 22.38 Torr.a. 911 mLb. 301 mLc. 605 mLd. 1820 mLe. 940 mL

Problem

According to the equation 2 KCIO 3(s) → 2 KCI(s) + 3 O 2(g)

A 3.00 g sample of KCIO 3 (122.5 g/mol) decomposes and the oxygen is collected over water at 24.0°C and 0.982 atm. What volume of oxygen gas will be collected, assuming 100% yield? P(H 2O) at 24.0°C = 22.38 Torr.

a. 911 mL

b. 301 mL

c. 605 mL

d. 1820 mL

e. 940 mL