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Problem: The following three questions are based on the following reaction:2 Cr + 3 ClO2 – + 3 H2O → 2 Cr(OH)3 + 3 ClO –The reducing agent is:a) Crb) ClO2c) H2Od) Cr(OH)3e) ClO The oxidizing agent is:a) Crb) ClO2c) H2Od) Cr(OH)3e) ClO The oxidation number of chromium on the right hand side of the equation is:a) 2b) -2c) 3d) 4e) 6

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Problem Details

The following three questions are based on the following reaction:

2 Cr + 3 ClO2 + 3 H2O → 2 Cr(OH)3 + 3 ClO

The reducing agent is:

a) Cr

b) ClO2

c) H2O

d) Cr(OH)3

e) ClO

The oxidizing agent is:

a) Cr

b) ClO2

c) H2O

d) Cr(OH)3

e) ClO

The oxidation number of chromium on the right hand side of the equation is:

a) 2

b) -2

c) 3

d) 4

e) 6

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Our tutors have indicated that to solve this problem you will need to apply the Redox Reactions concept. If you need more Redox Reactions practice, you can also practice Redox Reactions practice problems.

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