Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The following three questions are based on the following reaction: 2 Cr + 3 ClO2 – + 3 H2O → 2 Cr(OH)3 + 3 ClO – The reducing agent is: a) Cr b) ClO2 c) H2O d) Cr(OH)3 e) ClO   The oxidizing

Problem

The following three questions are based on the following reaction:

2 Cr + 3 ClO2 + 3 H2O → 2 Cr(OH)3 + 3 ClO

The reducing agent is:

a) Cr

b) ClO2

c) H2O

d) Cr(OH)3

e) ClO

 

The oxidizing agent is:

a) Cr

b) ClO2

c) H2O

d) Cr(OH)3

e) ClO

 

The oxidation number of chromium on the right hand side of the equation is:

a) 2

b) -2

c) 3

d) 4

e) 6