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An electrochemical cell has the following half cell reactions:
Cu2+(aq) +2e- → Cu(s) E°1/2 = +0.34
Zn2+(aq) + 2e- → Zn(s) E°1/2 = -0.76
If the cell operates with the Cu electrode as the cathode and the Zn as the anode, What is the cell potential when the [Cu2+] = 0.001M and the [Zn2+] = 0.1M?
B) -1.159 V
C) +0.479 V
D) -0.479 V
E) +1.041 V
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Based on our data, we think this problem is relevant for Professor TBA's class at UBC.