Ch.18 - ElectrochemistryWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Use the standard half-cell potentials listed below to calculate the standard cell potential, E°cell, for the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.

Solution: Use the standard half-cell potentials listed below to calculate the standard cell potential, E°cell, for the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.

Problem

Use the standard half-cell potentials listed below to calculate the standard cell potential, E°cell, for the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.)
3 Br2(l) + 2 Fe(s) → 6Br1-(aq) + 2Fe2+(aq)
Br2(l) + 2 e- → 2 Br1-(aq)                 E° = +1.09 V
Fe2+(aq) + 2 e- → Fe(s)                   E° = -0.45 V


A) +0.64V
B) -0.64 V
C) -1.54 V
D) +1.54 V
E) the standard cell potential is 0.0v

Solution

We’re being asked to determine the standard cell potential (E°cellof the reaction occurring in an electrochemical cell. To calculate for the standard cell potential, use the following equation:


When a balanced reaction is given, identify the anode and the cathode half-reactions by determining the changes in oxidation states of each species based on the given reaction:

Recall:

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