Ch.18 - ElectrochemistrySee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Given Cu2+(aq) + 2e- → Cu(s)      E° = 0.337 V Al3+(aq) + 3e- → Al(s)         E° = -1.66 V Na+(aq) + e- → Na(s)          E° = -2.714 V. Which of the following reactions will occur? A) 2Na+(aq) + Cu(s) → Cu2+(aq) + 2Na(s)              E°cell = -3.051 V B) Al(s) + 3Na+(aq) → Al3+(aq) + 3Na(s)                E°cell = -1.054 V C) 2Na(s) + Cu2+(aq) → Cu(s) + 2Na+(aq)              E°cell = 3.051 V D) 2Al3+(aq) + 3Cu(s) → 3Cu2+(aq) + 2Al(s)          E°cell = -1.991 V E) 2Al3+(aq) + 3Cu(s) → 3Cu2+(aq) + 2Al(s)           E°cell = 1.991 V

Problem

Given

Cu2+(aq) + 2e- → Cu(s)      E° = 0.337 V

Al3+(aq) + 3e- → Al(s)         E° = -1.66 V

Na+(aq) + e- → Na(s)          E° = -2.714 V.

Which of the following reactions will occur?

A) 2Na+(aq) + Cu(s) → Cu2+(aq) + 2Na(s)              cell = -3.051 V

B) Al(s) + 3Na+(aq) → Al3+(aq) + 3Na(s)                cell = -1.054 V

C) 2Na(s) + Cu2+(aq) → Cu(s) + 2Na+(aq)              cell = 3.051 V

D) 2Al3+(aq) + 3Cu(s) → 3Cu2+(aq) + 2Al(s)          cell = -1.991 V

E) 2Al3+(aq) + 3Cu(s) → 3Cu2+(aq) + 2Al(s)           cell = 1.991 V