Ch. 17 - Chemical ThermodynamicsSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The temperature at which the following process reaches equilibrium at 1.0 atm is the normal boiling point of hydrogen peroxide. (R = 8.314 J•K-1•mol-1)H2O2(l) ⇌ H2O2(g)Use the following thermodynamic information at 298 K to determine this temperature.Substance:                H 2O2(l)              H2O2(g)ΔH°f (kJ/mol):             -187.7             -136.3ΔG°f (kJ/mol):             -120.4             -105.6S°   (J/K•mol):              109.6               232.7A) 120°CB) 144°CC) 196°CD) 418°CE) 585°C

Problem

The temperature at which the following process reaches equilibrium at 1.0 atm is the normal boiling point of hydrogen peroxide. (R = 8.314 J•K-1•mol-1)

H2O2(l) ⇌ H2O2(g)

Use the following thermodynamic information at 298 K to determine this temperature.

Substance:                H 2O2(l)              H2O2(g)
ΔH°f (kJ/mol):             -187.7             -136.3
ΔG°f (kJ/mol):             -120.4             -105.6
S°   (J/K•mol):              109.6               232.7

A) 120°C

B) 144°C

C) 196°C

D) 418°C

E) 585°C