Ch.16 - Aqueous Equilibrium See all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Determine the molar solubility of Al(OH)3 in a solution containing 0.050 M KOH. Ksp (Al(OH)3) = 1.9 x 10 -33 A) 1.0 x 10-11 M B) 5.0 x 10-7 M C) 4.75 x 10-36 M D) 1.5 x 10-29 M E) 0.050 M

Problem

Determine the molar solubility of Al(OH)3 in a solution containing 0.050 M KOH.

Ksp (Al(OH)3) = 1.9 x 10 -33

A) 1.0 x 10-11 M

B) 5.0 x 10-7 M

C) 4.75 x 10-36 M

D) 1.5 x 10-29 M

E) 0.050 M