Ch.14 - Chemical EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The reaction below has an equilibrium constant of  Kp = 2.26 x 104 at 298 K. CO(g) + 2H2(g) ⇌ CH3OH(g)What is the value of K p for the reaction below? AND Will the reaction products or reactants be favored at Equilibrium?1/2CH3OH(g) ⇌ 1/2CO(g) + H2(g)A) Kp = -2.26 x 10;  Products are favoredB) Kp = 4.4 x 10 ;    Reactants are favoredC) Kp = 6.7 x 10 –3 ;    Products are favoredD) Kp = 6.7 x 10 –3 ;     Reactants are favoredE) Kp = 1.5 x 10 2 ;      Products are favored

Solution: The reaction below has an equilibrium constant of Kp = 2.26 x 104 at 298 K.CO(g) + 2H2(g) ⇌ CH3OH(g)What is the value of K p for the reaction below? AND Will the reaction products or reactants be favo

Problem

The reaction below has an equilibrium constant of 
Kp = 2.26 x 104 at 298 K.
CO(g) + 2H2(g) ⇌ CH3OH(g)

What is the value of K p for the reaction below? AND Will the reaction products or reactants be favored at Equilibrium?

1/2CH3OH(g) ⇌ 1/2CO(g) + H2(g)

A) Kp = -2.26 x 10;  Products are favored

B) Kp = 4.4 x 10 ;    Reactants are favored

C) Kp = 6.7 x 10 –3 ;    Products are favored

D) Kp = 6.7 x 10 –3 ;     Reactants are favored

E) Kp = 1.5 x 10 2 ;      Products are favored