# Problem: How many mL of 0.024 M HCIO 4 would be required to reach the equivalence point in a titration of 32.00 mL of 0.017 M Ca(OH)2?A. 22.67 mLB. 45.33 mLC. 32.00 mLD. 11.33 mLE. 16.00 mL

###### FREE Expert Solution
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###### FREE Expert Solution

We’re being asked to calculate the volume (in mL) of 0.024 M HClO4 (strong acid) required to reach the equivalence point in a titration of 32.00 mL of 0.017 M Ca(OH)2 (strong base)

Recall that at the equivalence point of a titration:

Also, recall that moles = molarity × volume

This means:

$\overline{){\left(\mathbf{MV}\right)}_{{\mathbf{acid}}}{\mathbf{=}}{\left(\mathbf{MV}\right)}_{{\mathbf{base}}}}$

95% (351 ratings)
###### Problem Details

How many mL of 0.024 M HCIO 4 would be required to reach the equivalence point in a titration of 32.00 mL of 0.017 M Ca(OH)2?

A. 22.67 mL
B. 45.33 mL
C. 32.00 mL
D. 11.33 mL
E. 16.00 mL

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Equivalence Point concept. If you need more Equivalence Point practice, you can also practice Equivalence Point practice problems.

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Our tutors rated the difficulty ofHow many mL of 0.024 M HCIO 4 would be required to reach the...as medium difficulty.

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Based on our data, we think this problem is relevant for Professor Crisostomo's class at AU.