We’re being asked to **calculate the volume (in mL) of 0.024 M HClO _{4} (strong acid)** required to reach the equivalence point in a titration of

Recall that at the ** equivalence point** of a titration:

$\overline{){\mathbf{moles}}{\mathbf{}}{\mathbf{acid}}{\mathbf{=}}{\mathbf{moles}}{\mathbf{}}{\mathbf{base}}}$

Also, recall that **moles = molarity × volume**.

This means:

$\overline{){\left(\mathbf{MV}\right)}_{{\mathbf{acid}}}{\mathbf{=}}{\left(\mathbf{MV}\right)}_{{\mathbf{base}}}}$

How many mL of 0.024 M HCIO _{4} would be required to reach the equivalence point in a titration of 32.00 mL of 0.017 M Ca(OH)_{2}?

A. 22.67 mL

B. 45.33 mL

C. 32.00 mL

D. 11.33 mL

E. 16.00 mL

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