We’re being asked to determine the temperature at which the rate constant of a reaction is 1521 s–1.
We’re given the rate constant at another temperature and the activation energy of the reaction. This means we need to use the two-point form of the Arrhenius Equation:
k1 = rate constant at T1
k2 = rate constant at T2
Ea = activation energy (in J/mol)
R = gas constant (8.314 J/mol•K)
T1 and T2 = temperature (in K).
When a reaction is run at 150.0°C, data shows that k = 28.68 s -1 and Ea = 36.25 kJ/mol. What temperature would the reaction have to be run in order for k to be 1521 s-1?
a. 234.8 °C
b. 274.1 °C
c. 414.9 °C
d. 173.7 °C
e. -1.11 °C
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Arrhenius Equation concept. You can view video lessons to learn Arrhenius Equation. Or if you need more Arrhenius Equation practice, you can also practice Arrhenius Equation practice problems.
What is the difficulty of this problem?
Our tutors rated the difficulty ofWhen a reaction is run at 150.0°C, data shows that k = 28.68...as medium difficulty.
How long does this problem take to solve?
Our expert Chemistry tutor, Dasha took 8 minutes and 44 seconds to solve this problem. You can follow their steps in the video explanation above.