Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Which of the following is the correct K b expression for the reaction below: B(aq) + H2O(l) ⇌ HB+(aq)OH-(aq)A) Kb = [B][H2O]B) Kb = [HB+][OH-] / [B][H2O]C) Kb = [HB+][OH-] / [H2O]D) Kb = [HB+][OH-] / [B]E) Kb = [HB+][OH-]

Solution: Which of the following is the correct K b expression for the reaction below:B(aq) + H2O(l) ⇌ HB+(aq) + OH-(aq)A) Kb = [B][H2O]B) Kb = [HB+][OH-] / [B][H2O]C) Kb = [HB+][OH-] / [H2O]D) Kb = [HB+][OH-]

Problem

Which of the following is the correct K b expression for the reaction below:
B(aq) + H2O(l) ⇌ HB+(aq)OH-(aq)

A) Kb = [B][H2O]

B) Kb = [HB+][OH-] / [B][H2O]

C) Kb = [HB+][OH-] / [H2O]

D) Kb = [HB+][OH-] / [B]

E) Kb = [HB+][OH-]

Solution

We are being asked to determine the correct Kb expression for the given reaction below:

Equilibrium reaction:        B(aq) + H2O(l)  HB+(aq) + OH-(aq)


Kb is the base dissociation constant and it is an equilibrium expression

When writing an equilibrium expression:

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