Problem: A plot of k versus 1/T has a slope of -7,445. What is E a, for this reaction?A, 90.79 kJ/molB. 895.5 J/molC. 304.7 kJ/molD. 61.90 kJ/molE. 610.5 J/mol

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We’re being asked to determine the activation energy (Ea) of a reaction given that the plot of k vs. 1/T has a slope of –7445.

We’re given the plot of k (y) vs. 1/T (x)

This means we need to use the two-point form of the Arrhenius Equation:

ln k=-EaR 1T + ln A


k = rate constant

Ea = activation energy (in J/mol)

R = gas constant (8.314 J/mol • K)

T = temperature (in K)

A = Arrhenius constant or frequency factor

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Problem Details

A plot of k versus 1/T has a slope of -7,445. What is E a, for this reaction?

A, 90.79 kJ/mol

B. 895.5 J/mol

C. 304.7 kJ/mol

D. 61.90 kJ/mol

E. 610.5 J/mol

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