Ch.13 - Chemical KineticsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: For the first-order reaction, the initial concentration of reactant A is 0.882 M. What would be concentration be after 8 half-lives?a. 0.110 Mb. 0.353 Mc. 0.00345 Md. 0.00143 Me. 0.00200 M

Solution: For the first-order reaction, the initial concentration of reactant A is 0.882 M. What would be concentration be after 8 half-lives?a. 0.110 Mb. 0.353 Mc. 0.00345 Md. 0.00143 Me. 0.00200 M

Problem

For the first-order reaction, the initial concentration of reactant A is 0.882 M. What would be concentration be after 8 half-lives?

a. 0.110 M
b. 0.353 M
c. 0.00345 M
d. 0.00143 M
e. 0.00200 M

Solution

We’re being asked to calculate the amount of A remaining after 8 half-lives if we start with 0.882 M A. 


Recall that half-life is the time needed for the amount of a reactant to decrease by 50% or one-half. One way to determine the amount remaining after x half-lives is:



where [A]t = concentration after x half-lives, [A]0 = initial concentration and x = number of half-lives.


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