Ch.12 - SolutionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: NOTE: Glycerine is a nonelectrolyte.30.2 g of glycerine (C3H8O3, with MW 92.1 g/mol) are dissolved in 150 g of the solution. What is the new boiling point of solution?(Kb of water = 0.515°C/m)1. 101.52°C2. 1.13°C3. 101.13°C4. 0.104°C5. 100.10°C

Solution: NOTE: Glycerine is a nonelectrolyte.30.2 g of glycerine (C3H8O3, with MW 92.1 g/mol) are dissolved in 150 g of the solution. What is the new boiling point of solution?(Kb of water = 0.515°C/m)1. 101.5

Problem

NOTE: Glycerine is a nonelectrolyte.

30.2 g of glycerine (C3H8O3, with MW 92.1 g/mol) are dissolved in 150 g of the solution. What is the new boiling point of solution?

(Kb of water = 0.515°C/m)

1. 101.52°C

2. 1.13°C

3. 101.13°C

4. 0.104°C

5. 100.10°C