Ch.16 - Aqueous Equilibrium See all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Ksp = 4.64 × 10 −3 for Ba(NO3)2. What is the concentration of the nitrate ion in a saturated Ba(NO3)2 solution?  A. 0.105 M B. 0.167 M C. 0.210 M D. 0.333 M E. 0.068 M F. 0.136 M

Problem

Ksp = 4.64 × 10 −3 for Ba(NO3)2. What is the concentration of the nitrate ion in a saturated Ba(NO3)2 solution? 

A. 0.105 M

B. 0.167 M

C. 0.210 M

D. 0.333 M

E. 0.068 M

F. 0.136 M