Ch.18 - ElectrochemistryWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: If the following half-reactions are used in an electrolytic cell:Li +(aq) +  e  →  Li(s)          E  0 = − 3.04Mg 2+(aq) + 2e  →  Mg(s)   E 0 = − 2.38And 10 Amps are applied for 1 minute, determine which solid would form and how much would form in grams. A. 0.043 grams of LithiumB. 0.022 grams of LithiumC. 0.15 grams of MagnesiumD. 0.076 grams of MagnesiumE. 0.086 grams of Lithium  

Solution: If the following half-reactions are used in an electrolytic cell:Li +(aq) +  e−  →  Li(s)          E  0 = − 3.04Mg 2+(aq) + 2e−  →  Mg(s)   E 0 = − 2.38And 10 Amps are applied for 1 minute, determine

Problem

If the following half-reactions are used in an electrolytic cell:

Li +(aq) +  e  →  Li(s)          E  0 = − 3.04

Mg 2+(aq) + 2e  →  Mg(s)   E 0 = − 2.38

And 10 Amps are applied for 1 minute, determine which solid would form and how much would form in grams.

 

A. 0.043 grams of Lithium

B. 0.022 grams of Lithium

C. 0.15 grams of Magnesium

D. 0.076 grams of Magnesium

E. 0.086 grams of Lithium