We’re being asked to **determine the volume (in mL) of solution** that would contain **0.10 mol sucrose in a 0.40 molal solution**.

Recall that ** molality** is the ratio of the moles of solute and the mass of solvent (in kilograms).

In other words:

$\overline{){\mathbf{Molality}}{\mathbf{\left(}}{\mathbf{m}}{\mathbf{\right)}}{\mathbf{=}}\frac{\mathbf{moles}\mathbf{}\mathbf{solute}}{\mathbf{kg}\mathbf{}\mathbf{solvent}}}$

The mass of the solution is simply **mass of solute + mass of solvent**.

**For this problem, we need to do the following steps:**

* Step 1:* Determine the mass of sucrose (solute).

* Step 2:* Determine the mass of benzene (solvent).

* Step 3:* Calculate the mass and volume of the solution.

A solution of sucrose (C_{12}H_{22}O_{11} of MW 342 grams/mole) in benzene is 0.40 molal. The solution’s density is 0.90 grams/mL. How many milliliters of the solution would contain 0.10 moles of sucrose?

1. 444 mL

2. 316 mL

3. 250 mL

4. 360 mL

5. 225 mL

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