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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: A solution of sucrose (C12H22O11 of MW 342 grams/mole) in benzene is 0.40 molal. The solution’s density is 0.90 grams/mL. How many milliliters of the solution would contain 0.10 moles of sucrose?1. 44

Solution: A solution of sucrose (C12H22O11 of MW 342 grams/mole) in benzene is 0.40 molal. The solution’s density is 0.90 grams/mL. How many milliliters of the solution would contain 0.10 moles of sucrose?1. 44

Problem

A solution of sucrose (C12H22O11 of MW 342 grams/mole) in benzene is 0.40 molal. The solution’s density is 0.90 grams/mL. How many milliliters of the solution would contain 0.10 moles of sucrose?

1. 444 mL

2. 316 mL 

3. 250 mL

4. 360 mL

5. 225 mL

Solution

We’re being asked to determine the volume (in mL) of solution that would contain 0.10 mol sucrose in a 0.40 molal solution.


Recall that molality is the ratio of the moles of solute and the mass of solvent (in kilograms)


In other words:


Molality(m)=moles solutekg solvent


The mass of the solution is simply mass of solute + mass of solvent


For this problem, we need to do the following steps:

Step 1: Determine the mass of sucrose (solute).

Step 2: Determine the mass of benzene (solvent).

Step 3: Calculate the mass and volume of the solution.


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